Comments on: How do you figure KWH savings by turning off lighting loads at night when you know amperage? http://www.homelightingco.com/how-do-you-figure-kwh-savings-by-turning-off-lighting-loads-at-night-when-you-know-amperage/ Interior and Outdoor Lighting Tue, 26 Oct 2010 13:46:05 -0600 http://wordpress.org/?v=2.8.6 hourly 1 By: billrussell42 http://www.homelightingco.com/how-do-you-figure-kwh-savings-by-turning-off-lighting-loads-at-night-when-you-know-amperage/comment-page-1/#comment-860 billrussell42 Mon, 15 Mar 2010 03:27:26 +0000 http://www.homelightingco.com/how-do-you-figure-kwh-savings-by-turning-off-lighting-loads-at-night-when-you-know-amperage/#comment-860 if 250 amps is the sum of the currents in all 3 phases, then wattage is 120 x 250 watts. Divide by 1000 to get kW, and multiply by 8 hours to get kW-hrs. Then multiply by cost per kW-hr (7¢ is more likely than 0.07¢) . [who]<a href="http://www.greatjewelrydesign.com/blog/"> billrussell42</a> if 250 amps is the sum of the currents in all 3 phases, then wattage is 120 x 250 watts. Divide by 1000 to get kW, and multiply by 8 hours to get kW-hrs.

Then multiply by cost per kW-hr (7¢ is more likely than 0.07¢)

. [who] billrussell42

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